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電阻問題小討論 !??

Aug 19th 2013, 05:06

單獨R1情形: V=I1*R1
兩者串聯: V=I *(R1+R2)

兩式左邊相等, 所以右邊也相等: I1 *R1 = I *(R1+R2)
I1* 較小數= I * 較大數
所以I1較大, I較小
可知: I <I1

則通過R1的電流I1，此時會小於先前的電流!

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