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四題數學題
Aug 21st 2013, 13:22

(1)已知正整數a介於200與400之間,以3除之餘1,以5除之餘1,滿足條件的a有多少個?

3除之餘1,以5除之餘1最小的數為16

故介於200與400之間,滿足的a一共有211~391一共180/15+1=13個

(2)正整數n以4、6、7除之均得餘數1,那麼n以84除之得餘數為何?

正整數n以4、6、7除之均得餘數1

換句話說,n除以(4,6,7)的最小公倍數均得餘數1

其中(4,6,7)的最小公倍數為84

(3)因式分解:9X^4-7X^2+1

無法被因式分解

(4)二次函數y=ax^2+bx+c (頂點位於第一象限,開口朝下)
試判定a、b、c、b^2-4ac之正負。

二次函數開口朝下→a<0
頂點在第一象限→(-b/2a, c-b^2/4a)在第一象限
→b/2a<0, c-b^2/4a>0
→b>0, b^2-4ac>0

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